”HDOJ Java“ 的搜索结果

     原题 http://acm.hdu.edu.cn/game/entry/problem/show.php?chapterid=1&sectionid=3&problemid=11 源码 import java.util.*; public class Main { public static void main(String[] args) { ... Scan...

(HDOJ)排名-Java实现

标签:   ACM  Java

     原题 http://acm.hdu.edu.cn/game/entry/problem/show.php?chapterid=1&sectionid=3&problemid=5 源码 import java.util.*; public class Main { public static void main(String[] args) { Scanne...

     #include using namespace std; int main(void) {  int n;  while (cin >> n && n != 0)  {  int *a = new int[n];  int i;  for (i = 0; i  {  cin >

     一、勾上你选用的语言 二、注意类名 public class Main{ } 三、注意要循环输入 Scanner scanner = new Scanner(System.in); while (scanner.hasNext()) { String strs = scanner.nextLine();......

     数据的交换输出 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 54598 Accepted Submission(s): 20730 Problem Description ...Inpu

     题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1063 思路:最近刚学了java,然后就迫不及待想试试java写大数的好处了,呵呵,果然是很方便啊! 1 import java.math.BigDecimal;... 5 public c...

     /* 偶数求和 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 44974 Accepted Submission(s): 19652 Problem Description 有一个长度为n(n ...

     #include<iostream> using namespace std; int main() { char a[4]; while(cin >> a) { /*for( int i = 0;i < 3;i ++) { cin &gt...

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